IPL 2021: MI vs CSK Preview – The heavyweights meet in highly-anticipated clash
In each and every season we look forward to one derby, which brings out a lot of fireworks. As we progress towards the second half of the IPL 2021, Mumbai Indians are all set to take on Chennai Super Kings in the national capital. Unlike each year, this time around, Mumbai haven’t started off well, but are slowly getting into the thick of things.
In their six matches so far, the five-time champs Mumbai have lost three and won three, one of which was against Rajasthan just a couple of days ago. Chennai, on the other hand, is coming into this clash having won five of their six matches. CSK have looked quite dominant so far in this league, and it can be said that they will start as favourites.
Match Info
IPL 2021 Match 27– Mumbai Indians vs Chennai Super Kings
Venue: Arun Jaitley’s Stadium, Delhi
Time: 7:30 PM IST
Head to head:
Stat Attack:
Krunal Pandya needs 1 more wicket to reach 50 IPL wickets for MI.
Rohit Sharma is 4 sixes away from completing 400 sixes across T20s.
Team News:
Mumbai Indians: Mumbai Indians made an odd change in the previous match where they dropped Ishan Kishan and played Nathan Coulter-Nile, making him bowl four overs and batting at no.7. He is fit for both roles but might be batting one position higher than usual. Having said that, he should be retained in the XI. Jayant Yadav, the off-spinner took a bit of hammering in the previous match, which might make Rohit Sharma drop him and bring back Ishan to restore the balance.
Chennai Super Kings: Chennai were forced to leave out Imran Tahir in order to bring in Moeen Ali in the scheme of things in the previous match. That move should continue, given how spinners seemed slightly ineffective on this wicket. We could see Dwayne Bravo make a comeback in the line-up though. Lungi Ngidi and Bravo have switched places quite smartly during the course of this tournament and considering Bravo’s record against Mumbai, he should be slotted back in the XI. The rest of the line-up should remain unchanged.